C++ Pointer Arithmetic

Idea: Take 2 pointers and an array.  Point the 2 pointers at different elements in the array.  Taking the difference between the pointers yields the number of elements separating the 2 pointers.

Motivated by Liberty & Jones

Do you like this signature?  bool GetWord(char * theString, char* word, int& wordOffset)

check edge case of being at the end of string

work:  char * p1, *p2;

p1 = p2 = theString+wordOffset;

trim the leading spaces

determine whether you really have a word

p1 & p2 are at the beginning of same word, so move p2 to the end of the word

get the length by the diff of p2 & p1

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Chad Salinas